Monday

September 22, 2014

September 22, 2014

Posted by **Kelly** on Saturday, July 17, 2010 at 4:13pm.

Equation:35x^2+20y^2=1

Given that dx/dt=4, find dy/dt

when (x,y)=(1/7sqrt2, 1/5sqrt2)

- Calculus -
**Damon**, Saturday, July 17, 2010 at 4:58pm70 x dx/dt + 40 y dy/dt = 0

280 x + 40 y dy/dy = 0

280/7sqrt2 + 40/5sqrt2 dy/dt = 0

**Answer this Question**

**Related Questions**

Derivative Calculus - I just need my answers checked. 1) Find the derivative. f(...

Calculus derivative - find the slope m and an equation of the tangent line to ...

Math - derivative of sinusoidal (check) - a) Find a function y=f(x) that ...

Calculus - Follow the steps below for the given function. (Do not use mixed ...

Calculus - R=M^2(c/2-m/3) dR/dM=CM-M^2 I found the derivative. Now how would I ...

calculus - First I would find the first derivative which is the slope and then ...

calculus - help needed!!! how would you go about drawing the graph of a ...

Calculus - I finished this problem but I wanted some feedback because I don't ...

Calculus - find derivitive of 1/square root of x 1/square root of x = x^(-1/2) ...

Calculus--> bobpursley - How do you get m=0? from taking the second ...