Thursday

March 5, 2015

March 5, 2015

Posted by **Stephanie** on Saturday, July 17, 2010 at 10:13am.

- Physics -
**drwls**, Saturday, July 17, 2010 at 11:04ama) Maximum velocity, which happens at the equilibrium point, is

Vmax = A*w, where w is the angular frequency, in radians per second.

In this case,

w = 3.0 * 2 pi = 6.28 radians/s

Vmax = 0.13m*6.28 rad/s = 0.816 m/s

b) 0.1 m from equilibrium is 0.1/0.13 = 76.92% of maximum deflection, and will have 0.7692^2 = 59.17% of maximum spring potential energy, which is 59.17% of total energy.

1-0.5917 = 40.83% of the energy will be kinetic energy at 0.1 m stretch.

Velocity wil be sqrt(0.4083)= 63.90% of maximum, or 0.521 m/s

c) (1/2) M*Vmax^2 = maximum KE

Do the numbers

d) X = (amplitude)*cos (wt)

= 0.13 cos(6.28 t)

(It could also be negatve)

- Physics -
**George**, Thursday, November 29, 2012 at 1:43pmThis is WRONG. Did not multiply the 2pi by 3. You just did 2pi

**Answer this Question**

**Related Questions**

Physics - A 0.70 kg mass at the end of a spring vibrates 4.0 times per second ...

Physics - A 0.52kg mass at the end of a spring vibrates 4.0 times per second ...

Physics - A 0.50-kg mass at the end of a spring vibrates 3.0 times per second ...

physics - A 0.50 kg mass at the end of a spring vibrates 6.0 times per second ...

physics - a 0.25 kg mass at the end of a spring oscillates 2.2 times per second ...

Physics - A spring force constant 210 N/m vibrates with an amplitude of 28.0 cm ...

physics - a vertical spring with spring stiffness constant 305 n/m oscillates ...

Physics 203 - A block with mass of 5.0kg is suspended from an ideal spring ...

Physics - Placing a 215 g mass on a vertical spring causes a stretch of 5.1 cm. ...

trig - A spring is attached to the ceiling and pulled 17 cm down from ...