Posted by **Sam** on Friday, July 16, 2010 at 7:26pm.

A 17.0-kg satellite has a circular orbit with a period of 2.31 h and a radius of 9.10×106 m around a planet of unknown mass. If the magnitude of the gravitational acceleration on the surface of the planet is 8.10 m/s2, what is the radius of the planet?

radius = m

- physics -
**bobpursley**, Friday, July 16, 2010 at 7:35pm
figure the centripetal acceleration v^2/r

where v=2PIr/T you are given r as 9.10E6

now set that acceleration equal to

8.10*(rp/9.1E6)^2 and solve for the radius of the planet rp.

- physics -
**Sam**, Saturday, July 17, 2010 at 12:52pm
What is Plr?

- math -
**nana**, Saturday, July 17, 2010 at 6:26pm
Which values are solutions to the inequality below? Check all that apply. sqrtx

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