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November 22, 2014

November 22, 2014

Posted by **Krsz** on Friday, July 16, 2010 at 8:49am.

(cot30deg) (sec45deg)

- trig -
**Reiny**, Friday, July 16, 2010 at 9:10amyour teacher probably expects you to know the ratios of sides of the 30-60-90 and the 45-45-90 triangles

they are

1 : √3 : 2 and 1 : 1 : √2

make a sketch to see the sides and the sides

so cot30°sec45°

= √3√2 = √6

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