Posted by Krsz on .
Find the values of the followin:
(cot30deg) (sec45deg)

trig 
Reiny,
your teacher probably expects you to know the ratios of sides of the 306090 and the 454590 triangles
they are
1 : √3 : 2 and 1 : 1 : √2
make a sketch to see the sides and the sides
so cot30°sec45°
= √3√2 = √6