Posted by **josh** on Friday, July 16, 2010 at 6:28am.

a ball is thrown vertically upward from the ground with the velocity of 30m/s,

a)how long will it take to rise to its highest point?

b)how high does the ball rise?

c)how long after projection will the ball have the velocity of 10m/s upward?

tnx

- physics -
**drwls**, Friday, July 16, 2010 at 6:42am
The variation of height (y, in meters) with time (t, in seconds) is given by the equation

y = 30 t - (g/2) t^2

g is the accelertaion of gravty, 9.8 m/s^2.

(a) The highest value of y is obtained when the velccity V is zero.

V(t) = dy/dt = 30 - gt = 0

Solve for t.

(b) Use the value of t that you get in part (a) to solve for y(t) at that time.

(c) Set V(t) = +10 and solve for t.

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