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March 3, 2015

Posted by **Daisy** on Friday, July 16, 2010 at 1:09am.

a) 26.0 g object

b) 10.0 g object

- Physics -
**drwls**, Friday, July 16, 2010 at 7:09amThe center of mass of the two objects moves to the right at a velocity

(26*17 + 10*15)/(26 + 10) = 16.44 m/s

Consider what happens in a coordinate system travelling the the CM.

a) The heavier object comes from the right at velocity 17-16.44 = 0.56 cm/s and leaves at -0.56 cm/s.

b) The lighter object approaches from the left at velocity 15 - 16.44 = -1.44 cm/s and leaves with velocity +1.44 m/s.

Transfering back to lab coordinate sytem (by adding +16.44 to both velocities) , the final velocity of the heavier object is -0.56 + 16.44 = 15.88 cm/s, and the lighter object is +1.44 + 16.44 =

17.88 cm/s.

The above is a shortcut compared to solving both the momentum and energy cnservation equations for two unknowns. It should give the same reult if I did the math right.

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