This question is very confusing, I do not understand what it wants me to do.
Each reaction below has been identified by type. Use this information to help predict products. Copy and then complete each equation by writing the products of the reactions. Remember to include subscripts and parentheses when required.
This is what I did, not quite understanding what I was supposed to do.
A) Al + F2 --> Synthesis
Products: 1 atom of aluminum metal, 2 molecules of fluorine gas.
2Al + 3F2 --> 2AlF3
B) K+O2 --> Synthesis
Products: 1 atom of potassium metal, 2 molecules of oxygen gas.
4K + O2 --> 2K2O
C) C2H6+O2 --> Combustion
Products: hydrocarbon, oxygen
C2H6 + 4O2 --> 2CO2 + 3H2O
D) C6H12O4 + O2--> Combustion
Products: Carbon, hydrogen, Oxygen
C6H12O4 + 7O2 --> 6CO2 + 6H2O
Is this what I'm supposed to do, or am I totally off track?
You are totally off track. Look at the first. The product is 2 molecules of aluminum floride, AlF3
I forgot to mention some parts.
Each reaction below has been identified by type. Use this information to help predict products. Copy and then complete each equation by writing the products of the reactions. Remember to include subscripts and parentheses when required.
It also says use the charges from a periodic table. I don't get what I'm supposed to do.
I get the product part now, thanks bobpursely, but have I done the rest of it correct, because I have balanced those equations, and it doesn't ask me in the question to do that, so I'm very unsure of what do do or not.
Just state the product, not the atoms involved. For instance, potassium oxide (K2O) is the product o...
After reviewing your work and the response by Bob Pursley, here is what I think.
I believe you have misinterpreted the question. Your answers for the type of reaction appear to be correct. The products appear to be correct. The balanced equations appear to be correct. What you have not done is to name the PRODUCTS. You have named the reactants and called them products. The products are on the right side of the arrow; the reactants are on the left side of the arrow. For example, in the example to which Bob P responded, the product is aluminum fluoride as he points out. You named the reactants as products but you wrote the equation correctly and balanced it.
They've given me the reaction type themselves, it was in the book. Also can you please stay on this site and provide me with help.
I'll try to write quickly and post what I've done on here, but please sir stay.
A) Al + F2 --> Synthesis
Products: 2 molecules of aluminum fluoride
2Al + 3F2 --> 2AlF3
B) K+O2 --> Synthesis
Products: 2 molecules of Potassium oxide
4K + O2 --> 2K2O
C) C2H6+O2 --> Combustion
Products: Carbon dioxide, water
C2H6 + 4O2 --> 2CO2 + 3H2O
D) C6H12O4 + O2--> Combustion
Products: Carbon dioxide, water
C6H12O4 + 7O2 --> 6CO2 + 6H2O
C) C2H6+O2 --> Combustion
Products: 2 molecules of Carbon dioxide, 3 molecules of water
C2H6 + 4O2 --> 2CO2 + 3H2O
D) C6H12O4 + O2--> Combustion
Products: 6 molecules of Carbon dioxide, 6 molecules of water
C6H12O4 + 7O2 --> 6CO2 + 6H2O
sorry I forgot to mention how many molecules before.
The decomposition is a bit harder for me than the rest. I looked over the examples in my book tons of times, but I still don't get it.
Rb2O --> Decomposition
Rb + O2
I don't know what to do rest.
I'm not sure I'll get all of your questions but...
1. Usually one balances an equation unless specifically told not to do so.
2. I don't think the question asks you to identify the number of molecules. I think it is sufficient to write, for example, aluminum fluoride, or carbon dioxide and water. I think the idea is for you to know the names of the compounds. Besides, there isn't enough information given to suggest 2 molecules of aluminum fluoride. It COULD be 2 moles or 2 grams and not 2 molecules.
3. Decomposition is the reverse of synthesis. In synthesis, the first question with Al and F2, you take two or more reactants and make a smaller number of particles. (You took two reactants and made one product). In decomposition reactions, you take one reactant and break it apart into two or more products. 2Rb2O ==> 4Rb + O2