posted by Si on .
Hi,I have a linear model with equation p = 5.1t - 28, where p is the number of breeding pairs of birds and t is the year. I need to use algebra to find the year in which the linear model predicts the breeding pairs will exceed 500.
Any help appreciated.
Solve the equation
5.1t - 28 = 500
5.1t = 472
t = 472/5.1 = ___ years
Looks like a long wait.
I am assuming that "year zero" is the year when p = 28, and the counting starts. It is not 1 AD
Si, I'm assuming you meant the number of years it takes for the breeding pairs to exceed 500
P = 5.1t -28 = 500 Solve for t:
t = 528 / 5.1 = 103.5 or 104 yrs..
Yes. I agree with your answer.