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July 23, 2014

July 23, 2014

Posted by **Si** on Thursday, July 15, 2010 at 3:14pm.

Any help appreciated.

- Algebra -
**drwls**, Thursday, July 15, 2010 at 3:28pmSolve the equation

5.1t - 28 = 500

5.1t = 472

t = 472/5.1 = ___ years

Looks like a long wait.

I am assuming that "year zero" is the year when p = 28, and the counting starts. It is not 1 AD

- Algebra -
**Henry**, Thursday, July 15, 2010 at 3:49pmSi, I'm assuming you meant the number of years it takes for the breeding pairs to exceed 500

P = 5.1t -28 = 500 Solve for t:

t = 528 / 5.1 = 103.5 or 104 yrs..

- Algebra -
**drwls**, Thursday, July 15, 2010 at 3:50pmYes. I agree with your answer.

- Algebra -
**Henry**, Friday, July 16, 2010 at 11:55amThanks

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