Posted by **david** on Thursday, July 15, 2010 at 1:35am.

A ladder resting against the side of a building reaches 32 ft up the building. If the ladder is 40 ft long, how far from the building is the base of the ladder?

- Pythagorean Theorem -
**Nat**, Thursday, July 15, 2010 at 2:28am
Draw the problem out, with a ladder leaning against the wall, and label the respective lengths. You will notice it forms a right-angle triangle, with the ladder as the hypotenuse.

So the theorem is

a^2+b^2 =c^2

where c represents the ladder length (the hypotenuse), and so a can represent the distance of the ladder from the base of the building (the answer), and b is where the ladder reaches on the building.

Therefore,

a^2+32^2=40^2

Since a is what we need, rearrange the above formula to solve for a and you will get your answer. (Remember the units ft)

- Pythagorean Theorem -
**david**, Thursday, July 15, 2010 at 2:20pm
24 ft

- Pythagorean Theorem -
**violet**, Saturday, September 11, 2010 at 10:07pm
The doorway of the family room measures 6 1/2 feet by 3 feet. What is the length of the diagonal of the doorway?

- Pythagorean Theorem -
**jake**, Sunday, August 25, 2013 at 7:59pm
help

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