Homework Help: chemistry

Posted by hongkong on Wednesday, July 14, 2010 at 11:02pm.

If the Kf value is known to be 2.0 x 10^3. The experimental values for Kf were found to be 1.0 x 10^3, 2.0 x 10^3, 3.0 x 10^3, 1.5 x 10^3 and 1.0 x 10^3. Using the absolute values of differences, calculate the average deviation from Kf.

Please show me the steps how to this problem. Thanks a lot!

chemistry - DrBob222, Wednesday, July 14, 2010 at 11:13pm
(2 x 10^3)-(1.0 x 10^3) = delta (difference) = 1.0 x 10^3

Do the same for the others (always subtracting the smaller from the larger), then average by adding and divide the sum by 4.
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Do the same with the other values.

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