Fely is twice as old as Mary. Five years hence, she will be 10 years older than Mary. Find the current age of each girl. With solution.
F=2M
F+5-10=M+5
Those are the equations, right?
mary=10y/o
fely=10y/o
To find the current age of Fely and Mary, let's represent their ages with variables.
Let's say the current age of Mary is represented by 'M'.
Since Fely is twice as old as Mary, we can represent Fely's current age as 2M.
Five years from now, Mary's age will be represented by 'M + 5' since she will have aged 5 years. Similarly, Fely's age will be '2M + 5' since she will also have aged 5 years.
According to the problem, Fely will be 10 years older than Mary five years from now:
2M + 5 = M + 5 + 10
Now, we can solve this equation to find the value of M, which represents Mary's current age:
2M + 5 = M + 5 + 10
Combine like terms: 2M + 5 = M + 15
Subtract M from both sides of the equation: M + 5 = 15
Subtract 5 from both sides of the equation: M = 10
Therefore, Mary's current age, represented by 'M,' is 10 years.
Now, we can substitute this value back into either equation to find Fely's current age:
Fely's current age = 2M = 2 * 10 = 20 years
So, Mary's current age is 10 years, and Fely's current age is 20 years.