how many moles of Ba(OH)2 are present in 225ml of 0.400 Ba(OH)2
9.00x10-2
That's right. M x L = moles.
To determine the number of moles of Ba(OH)2 in a given volume of a solution, we can use the formula:
Number of moles = Concentration (mol/L) x Volume (L)
In this case, the given concentration is 0.400 mol/L, and the volume is 225 mL. We need to convert the volume from milliliters to liters.
1 L = 1000 mL
Therefore, 225 mL = 225/1000 L = 0.225 L
Now we can calculate the number of moles:
Number of moles = 0.400 mol/L x 0.225 L
Number of moles = 0.090 mol
So, there are 0.090 moles of Ba(OH)2 present in 225 mL of 0.400 Ba(OH)2 solution.