Posted by JT on Tuesday, July 13, 2010 at 1:16am.
Are you looking for the roots of that equation? There are three of them. One of them is w=1. You can see that by inspection.
For the other roots, divide
w^3 + 5w^2 -w -5 by (w-1) and solve the resulting quadratic. You end up with
w^2 + 6w +5 = 0
That can be easily factored for the other two roots, which are both real.
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