A and B are ok. The others are not right.
For B, technically, I think HF should be called hydrogen fluoride since HF(aq) is hydrofluoric acid (that is a water soln of HF is called the acid).
For the others, let me remind you of a rule (I think) I wrote last night.
Rule. In balancing equations you may NOT change the subscripts. You may change ONLY the coefficients. Thus, Na(OH)2 and that kind of thing is a NO, NO. Try those again.
For C, look at the O and H. Those atoms don't balance.
C) H3PO3 + Ca(OH)2
= H3PO3 + 3CaOH2
Reactants: Phosphic acid, Calcium hydroxide
Products: Calcium phosphate, water
Could you provide me an example of what you mean by that rule. I sort of understand, but an example would be better.
E) H2SO4 + NaOH
= H2SO4+ 2NaOH --> 2H2O + Na2SO4
About the last 2 in Na2SO4, It should be a coefficient right? Not a subscript.
Reactants: Sulphic acid, sodium hydroxide
Products: Sodium sulphate, water
If you meant phosphoric acid, it should be H3PO4. I will use that anyway as an example. The rule is that you
1. Write the formula of the reactants and products.
2. Then balance the equation by changing th coefficients. You may not change any subscripts AFTER the formula has been determined. WHY? Because you change the formula when you change subscripts. That is, NaOH is sodium hydroxide and if you change that to Na(OH)2 to balance the OH ions somewhere, Na(OH)2 is not sodium hydroxide any longer. In fact, there is no such thing as Na(OH)2. The ONLY way to get two more OH ions there, is to write 2NaOH. True, that makes two more Na atoms, also, but such is life. That makes it necessary to change Na somewhere in order to balance the extra Na but it always works out.
H3PO4 + Ca(OH)2 ==> Ca3(PO4)3 + H2O
2H3PO4 + 3Ca(OH)2 ==> Ca3(PO4)2 + 6H2O
Note that the formula I started with in the first line are exactly the same as the balanced equation in the second line. I made everything balance without changing any subscripts. I changed only coefficients.
H2SO4 + NaOH ==> Na2SO4 + H2O
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
Same thing. Note the formulas in line 1 and line 2 are the exact same thing; however, I changed coefficients to balance the equation.
CH3COOH + NaOH ==> CH3COONa + H2O
Balanced as is.
CH3COOH is acetic acid and all four (4) H atoms are not acidic; only the one in bold print.
You may see this written as HC2H3O2, also, which is one way of showing that only the first H shown is acidic.
DrBob222 you have no clue how much you taught me in one day. Thank You so so much for this help of yours. How can I ever thank you.