chemistry
posted by THOMAS .
When you set up the ICE chart, are you supposed to bring the 0.05 to the product side to give you an equation of x^2 / x  0.05?

Thomas, with the equation I gave you before you really don't need an ICE chart.
I think I had
Kb = (Kw/Ka) = (HC2H3O2)(OH^)/(0.05)
1 x 10^014/1.8 x 10^5) = 5.55 x 10^10
so
5.55 x 10^10 = (X^2)/0.05
Then X^2 = 5.55 x 10^10 x 0.05
X = sqrt(5.55 x 10^10 x 0.05)
This is the OH^, convert to pOH, then to pH. 
Thank You, i got it. The answer was 8.7