posted by THOMAS .
When you set up the ICE chart, are you supposed to bring the 0.05 to the product side to give you an equation of x^2 / x - 0.05?
Thomas, with the equation I gave you before you really don't need an ICE chart.
I think I had
Kb = (Kw/Ka) = (HC2H3O2)(OH^-)/(0.05)
1 x 10^014/1.8 x 10^-5) = 5.55 x 10^-10
5.55 x 10^-10 = (X^2)/0.05
Then X^2 = 5.55 x 10^-10 x 0.05
X = sqrt(5.55 x 10^-10 x 0.05)
This is the OH^-, convert to pOH, then to pH.
Thank You, i got it. The answer was 8.7