Posted by Jas on .
Hi, I have to produce a sketch of a line that passes through the points (4,3) and (10,0), i have already worked its gradient out to be 0.5 and its y  intercepts as 5. For some reason i am having a mental block on the next bit! I need to add the line y = 6 to the sketch and then use algebra to find the coordinates of the point where the two lines intersect.
Please help

Maths 
Henry,
GIVEN: ( 4, 3 ), ( 10, 0 ).
m = 3/6 = 1/2 = 0.5
Find Equation of line:
Y = mX + b
3 = 1/2(4) + b.
Solve for b: b = 5.
Y = 1/2X +5
Substitute 6 for Y and solve for X.
6 = 1/2X + 5
1/2X = 1, X = 2. P ( 2, 6 ) is
where the lines intersect. Y = 6 is
a horizontal line 6 units above x
axis. Graph both lines and compare
point of intersection ( solution )
with calculated value.