Posted by **Jas** on Monday, July 12, 2010 at 12:04pm.

Hi, I have to produce a sketch of a line that passes through the points (4,3) and (10,0), i have already worked its gradient out to be -0.5 and its y - intercepts as 5. For some reason i am having a mental block on the next bit! I need to add the line y = 6 to the sketch and then use algebra to find the coordinates of the point where the two lines intersect.

Please help

- Maths -
**Henry**, Thursday, July 15, 2010 at 8:44pm
GIVEN: ( 4, 3 ), ( 10, 0 ).

m = -3/6 = -1/2 = -0.5

Find Equation of line:

Y = mX + b

3 = -1/2(4) + b.

Solve for b: b = 5.

Y = -1/2X +5

Substitute 6 for Y and solve for X.

6 = -1/2X + 5

1/2X = -1, X = -2. P ( -2, 6 ) is

where the lines intersect. Y = 6 is

a horizontal line 6 units above x

axis. Graph both lines and compare

point of intersection ( solution )

with calculated value.

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