posted by Jas .
Hi, I have to produce a sketch of a line that passes through the points (4,3) and (10,0), i have already worked its gradient out to be -0.5 and its y - intercepts as 5. For some reason i am having a mental block on the next bit! I need to add the line y = 6 to the sketch and then use algebra to find the coordinates of the point where the two lines intersect.
GIVEN: ( 4, 3 ), ( 10, 0 ).
m = -3/6 = -1/2 = -0.5
Find Equation of line:
Y = mX + b
3 = -1/2(4) + b.
Solve for b: b = 5.
Y = -1/2X +5
Substitute 6 for Y and solve for X.
6 = -1/2X + 5
1/2X = -1, X = -2. P ( -2, 6 ) is
where the lines intersect. Y = 6 is
a horizontal line 6 units above x
axis. Graph both lines and compare
point of intersection ( solution )
with calculated value.