how many grams of copper (II) Chloride are formed in the double replascement reaction of 1.1 g copper (II) oxide and excess hydrochloric acid?

CuO + 2HCl ==> CuCl2 + H2O

Convert 1.1 g CuO to moles. moles = grams/molar mass.

Using the coefficients in the balanced equation, convert moles CuO to moles CuCl2.

Now convert moles CuCl2 to grams. g = moles x molar mass.

To find out how many grams of copper (II) chloride are formed in the double replacement reaction, we need to set up a balanced chemical equation first.

The balanced equation for the reaction between copper (II) oxide and hydrochloric acid is:

CuO + 2HCl -> CuCl2 + H2O

From the equation, we can see that one mole of copper (II) oxide reacts with two moles of hydrochloric acid to form one mole of copper (II) chloride.

Now, let's calculate the moles of copper (II) oxide:

Molar mass of CuO = atomic mass of Cu + atomic mass of O
= (63.55 g/mol) + (15.999 g/mol)
= 79.55 g/mol

Moles of CuO = mass of CuO / molar mass of CuO
= 1.1 g / 79.55 g/mol
≈ 0.014 moles

Since the reaction is said to occur with an excess of hydrochloric acid, it means that all the copper (II) oxide will react, and no CuO will be left over.

According to stoichiometry, 1 mole of CuO reacts to form 1 mole of CuCl2. Therefore, the number of moles of CuCl2 formed will also be 0.014 moles.

Now, let's calculate the mass of copper (II) chloride:

Molar mass of CuCl2 = atomic mass of Cu + 2 * atomic mass of Cl
= (63.55 g/mol) + 2 * (35.453 g/mol)
= 134.003 g/mol

Mass of CuCl2 = moles of CuCl2 * molar mass of CuCl2
= 0.014 moles * 134.003 g/mol
≈ 1.876 g

Therefore, approximately 1.876 grams of copper (II) chloride are formed in the double replacement reaction.