Posted by Derrick on .
Balance each of the following skeleton equations. This is the last one left to balance.
D) C4H10 + O2 -> CO2 + H2O
= C4H10 + O2 -> 4CO2 + 10H
What you left is not balanced. Oxygen has 2 atoms on the left and 8 on the right. Second, H NEVER occurs as atomic H (unless we work on it to make it do it) but occurs as diatomic H as H2, Same for H2, O2, N2, Br2, Cl2, F2, I2 and their cousins P4 and S8.
2C4H10 + 13 O2 ==> 8CO2 + 10H2O