C12 H22 O11 = Co2 + H2O
how to balance this equation?
I don't think it will balance. Try this:
C12H22O11 + O2 >> CO2 + H2O
To balance the chemical equation:
C12 H22 O11 → CO2 + H2O
We need to make sure that the same number of atoms of each element are present on both sides of the equation.
Let's start with balancing the carbon (C) atoms:
The equation has 12 carbon atoms on the left side, which means we need 12 carbon atoms on the right side. We can achieve this by placing a 12 in front of CO2.
C12 H22 O11 → 12 CO2 + H2O
Next, let's balance the hydrogen (H) atoms:
The equation has 22 hydrogen atoms on the left side. To balance them, we need 11 water molecules (H2O), which will provide us with 22 hydrogen atoms. We add the coefficient 11 in front of H2O.
C12 H22 O11 → 12 CO2 + 11 H2O
Finally, let's balance the oxygen (O) atoms:
On the left side, we have 11 oxygen atoms from the sugar molecule and 22 oxygen atoms from the water molecules, resulting in a total of 33 oxygen atoms. To balance this, we need to place a coefficient of 33/2 (which simplifies to 16.5) in front of the sugar molecule, C12H22O11. However, we cannot have fractional coefficients in a balanced equation. So, to eliminate the fractional coefficient, we can multiply the entire equation by 2.
2 C12 H22 O11 → 24 CO2 + 22 H2O
Now, the equation is balanced, with 24 carbon atoms, 44 hydrogen atoms, and 66 oxygen atoms on both sides.