Thursday

December 18, 2014

December 18, 2014

Posted by **Dana** on Sunday, July 11, 2010 at 7:39pm.

- Algebra -
**Henry**, Sunday, July 11, 2010 at 10:44pmPerimeter = 230 Ft. The max. area will

occur as we approach a square (57.5)^2=

3306.25 sq. ft.). Since we are required to use a rectangle, the largest area we can get using whole

numbers is: A = LW = 58(57) = 3306 sq, ft. P = 58(2) + 57(2) = 230 ft as

required.

- Algebra -
**arnold**, Sunday, September 11, 2011 at 3:44pmIf a farmer has 280 feet of fence and wants to build a rectangle that the width is two-thirds of the length how do you calculate the deminsions?

**Answer this Question**

**Related Questions**

Math - The Maximum Garden Problem. A farmer has 230 ft of fence to enclose a ...

Math - A farmer has 230 ft of fence to enclose a rectangular garden. What is the...

algebra - A farmer decides to enclose a rectangular garden, using the side of a ...

algebra - A farmer decides to enclose a rectangular garden, using the side of a ...

Algebra - A farmer decides to enclose a rectangular garden, using the side of a ...

Math - 1. A gardener has 140 feet of fencing to fence in a rectangular vegetable...

Algebra - A gardener is putting a wire fence along the edge of his garden to ...

algebra2 - A farmer has 600 yards of fence. He will use some of the fence to ...

word problem - A farmer decides to enclose a rectangular garden, using the side...

Math - A farmer decides to enclose a rectangular garden, using the side of a ...