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July 30, 2014

July 30, 2014

Posted by **Dana** on Sunday, July 11, 2010 at 7:39pm.

- Algebra -
**Henry**, Sunday, July 11, 2010 at 10:44pmPerimeter = 230 Ft. The max. area will

occur as we approach a square (57.5)^2=

3306.25 sq. ft.). Since we are required to use a rectangle, the largest area we can get using whole

numbers is: A = LW = 58(57) = 3306 sq, ft. P = 58(2) + 57(2) = 230 ft as

required.

- Algebra -
**arnold**, Sunday, September 11, 2011 at 3:44pmIf a farmer has 280 feet of fence and wants to build a rectangle that the width is two-thirds of the length how do you calculate the deminsions?

- Algebra -
**arnold**, Sunday, September 11, 2011 at 3:44pmIf a farmer has 280 feet of fence and wants to build a rectangle that the width is two-thirds of the length how do you calculate the deminsions?

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