algebra
posted by sam .
find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function
f(x)=x^24x5

F(x) = Y = X^2  4X  5, h = Xv = b/2a
= 4/2 = 2, K = Yv = 2^2  4(2) 5 = 9
V(h,K), V(2,9). Since a is positive,
the graph opens upward and the vertex
is the min. point on thr graph. To graph the function,select values of X to the left and right of the vertex and
calculate the corresponding value of Y: (0,5) (1,8), V(2,9), (3,8),
(4,5).
Line of symmetry:X = 2
a = coefficient of X^2.
h = Xcoordinate of vertex.
K = Y coordinate of vertex.