Posted by **sam** on Sunday, July 11, 2010 at 7:29pm.

find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function

f(x)=x^2-4x-5

- algebra -
**Henry**, Monday, July 12, 2010 at 5:50pm
F(x) = Y = X^2 - 4X - 5, h = Xv = -b/2a

= 4/2 = 2, K = Yv = 2^2 - 4(2) -5 = -9

V(h,K), V(2,-9). Since a is positive,

the graph opens upward and the vertex

is the min. point on thr graph. To graph the function,select values of X to the left and right of the vertex and

calculate the corresponding value of Y: (0,-5) (1,-8), V(2,-9), (3,-8),

(4,-5).

Line of symmetry:X = 2

a = coefficient of X^2.

h = X-coordinate of vertex.

K = Y- coordinate of vertex.

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