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algebra

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find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function

f(x)=x^2-4x-5

  • algebra -

    F(x) = Y = X^2 - 4X - 5, h = Xv = -b/2a
    = 4/2 = 2, K = Yv = 2^2 - 4(2) -5 = -9
    V(h,K), V(2,-9). Since a is positive,
    the graph opens upward and the vertex
    is the min. point on thr graph. To graph the function,select values of X to the left and right of the vertex and
    calculate the corresponding value of Y: (0,-5) (1,-8), V(2,-9), (3,-8),
    (4,-5).
    Line of symmetry:X = 2

    a = coefficient of X^2.
    h = X-coordinate of vertex.
    K = Y- coordinate of vertex.

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