Posted by **sam** on Sunday, July 11, 2010 at 7:26pm.

determine the nature of the solutions of the equation. Two real solutions, two imaginary solutions, or one real solution.

2t^2-4t=0

- algebra -
**Tony**, Monday, July 12, 2010 at 8:07am
Here, discriminant = (-4)^2 = 16

Hence, discriminant is positive and greater than 0

Therefore, there are two real solutions of the given equation

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