Posted by **sam** on Sunday, July 11, 2010 at 7:21pm.

determine the nature of the solutions of the equation, one real solution, two real solutions, or two non-real solutions. x^2-20x+100=0

- algebra -
**Henry**, Monday, July 19, 2010 at 8:26pm
B^2 = 400, 4AC = 400, sqrt(400-400)= 0

Since the value under the radical = 0,

There iS 1 real solution.

## Answer this Question

## Related Questions

- algebra - determine the nature of the solutions of the equation. Two real ...
- Algebra - For the following equation, state the value of the discriminant and ...
- algebra - For the following equation, state the value of the discriminant and ...
- Math - For the following equation, state the value of the discriminant and then ...
- algebra - For the following equation, state the value of the discriminant and ...
- Algebra - How many real number solutions does the equation have? y=-4x^2+7x-8 A...
- Math 117 Algebra - for the following equation, state the value of the ...
- College Algebra 2 - for the following equation state the value of the ...
- Math - How many real number solutions does the equation have? y=3x^2-5x-5 A)one ...
- Math - 1)How many real number solutions does the equation have? -8x^2-8x-2=0 A) ...

More Related Questions