Posted by **sam** on Sunday, July 11, 2010 at 7:21pm.

determine the nature of the solutions of the equation, one real solution, two real solutions, or two non-real solutions. x^2-20x+100=0

- algebra -
**Henry**, Monday, July 19, 2010 at 8:26pm
B^2 = 400, 4AC = 400, sqrt(400-400)= 0

Since the value under the radical = 0,

There iS 1 real solution.

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