Posted by sam on Sunday, July 11, 2010 at 7:21pm.
determine the nature of the solutions of the equation, one real solution, two real solutions, or two nonreal solutions. x^220x+100=0

algebra  Henry, Monday, July 19, 2010 at 8:26pm
B^2 = 400, 4AC = 400, sqrt(400400)= 0
Since the value under the radical = 0,
There iS 1 real solution.
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