Posted by Scott on Sunday, July 11, 2010 at 8:04am.
y dy=4x^3 dx-dx
1/2 y^2=x^4-x + C
y= sqrt(2x^2-2x) + C1
dy/dx * y = 4x^3 -1
integral of y dy = integral of (4x^3-1)dx
y^2/2 = x^4 - x + C
9/2 = 1 -1 + C
C = 9/2
y^2 = 2x^4 -2x +9
y = -sqrt(2x^4 -x +9)
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