Write the equation of the lines.....best answer will be chosen
1. (3,-6) 7y+4y=5
2.(4,7) 7x+y=6
3.(-8,8) 5x=7y+6
4.(3,8) x+9y=2
your question makes no sense.
Are we testing if the given point is on the line?
Are we finding a new equation parallel to the give
equation and passing through the given point?
the only other info my teacher gives me is solve for y=
I restate my point ...
in the first question, you already have the equation of a line, but the point given does not satisfy that equation.
I am sure your teacher did not word the question the way you presented it here.
exactly I took it word for word
then sorry, I can't help you, I don't see a question that can be answered.
I went back she said using y-mx+b does this help?
To find the equation of the line in each of the given cases, we need to use the point-slope form of a line equation, which is y - y1 = m(x - x1), where (x1,y1) is a point on the line and m is the slope.
1. Let's find the slope of the line in the first equation. We have 7y + 4y = 5, which simplifies to 11y = 5. Dividing both sides by 11, we get y = 5/11. Since there is no x-term, the equation represents a horizontal line.
Since the line is horizontal, the slope is 0. The point given is (3,-6), so substituting these values into the point-slope equation, we have y - (-6) = 0(x - 3). Simplifying, we get y + 6 = 0, which can also be written as y = -6.
Therefore, the equation of the line is y = -6.
2. Let's find the slope of the line in the second equation. We have 7x + y = 6. Rearranging the equation in slope-intercept form (y = mx + b), we get y = -7x + 6. Comparing this with the point-slope form, we can see that the slope is -7.
The point given is (4, 7), so substituting these values into the point-slope equation, we have y - 7 = -7(x - 4). Simplifying, we get y - 7 = -7x + 28, which can also be written as y = -7x + 35.
Therefore, the equation of the line is y = -7x + 35.
3. Let's rearrange the third equation to get it in slope-intercept form. We have 5x = 7y + 6. Subtracting 7y from both sides, we get 5x - 7y = 6, which can also be written as -7y = -5x + 6. Dividing both sides by -7, we get y = 5/7x - 6/7.
The point given is (-8, 8), so substituting these values into the point-slope equation, we have y - 8 = 5/7(x - (-8)). Simplifying, we get y - 8 = 5/7x + 40/7, which can also be written as y = 5/7x + 40/7 + 56/7.
Therefore, the equation of the line is y = 5/7x + 96/7.
4. Let's rearrange the fourth equation to get it in slope-intercept form. We have x + 9y = 2. Subtracting x from both sides, we get 9y = -x + 2. Dividing both sides by 9, we get y = -1/9x + 2/9.
The point given is (3, 8), so substituting these values into the point-slope equation, we have y - 8 = -1/9(x - 3). Simplifying, we get y - 8 = -1/9x + 1/3, which can also be written as y = -1/9x + 1/3 + 24/3.
Therefore, the equation of the line is y = -1/9x + 25/3.