Posted by **Nev** on Friday, July 9, 2010 at 1:48am.

Hi,how do I find both solutions of the equation cos0 = 0.35 between degrees 0 and 360?

Many thanks

- trig -
**Reiny**, Friday, July 9, 2010 at 8:33am
the cosine is positive in the I and IV quadrant

using the inverse cosine function on your calculator

Ø = 69.513°

so Ø is either 69.513° or (360-69.513)° or 290.487°

- trig -
**Anonymous**, Monday, September 27, 2010 at 12:16am
i hope this is not ou question? as this is the exam cheat

- trig -
**Anonymous**, Monday, September 27, 2010 at 12:16am
i hope this is not ou question? as this is the exam cheat ...... YOU

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