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trig

posted by on .

Hi,how do I find both solutions of the equation cos0 = 0.35 between degrees 0 and 360?

Many thanks

  • trig - ,

    the cosine is positive in the I and IV quadrant

    using the inverse cosine function on your calculator

    Ø = 69.513°

    so Ø is either 69.513° or (360-69.513)° or 290.487°

  • trig - ,

    i hope this is not ou question? as this is the exam cheat

  • trig - ,

    i hope this is not ou question? as this is the exam cheat ...... YOU

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