math elimination method
posted by Lorri on .
elimination method really confuses me.
solve by elimination method
5r 3s = 17
3r + 5s =17
A. solution is ______ (ordered pair, integer or fraction)
B. Infinitely many
C. No Solution

try to get either the x or the y coefficients to be alike
in this case I will get the y's to have a 15 in front
so multiply the first by 5 and the second by 3 to get
25r  15s = 85
9r + 15s = 51
add them
34r = 136
r = 136/34 = 4
back in second, (or first)
3(4) + 5s = 17
12 + 5s = 17
5s = 5
s = 1 
thank you so much, i was not even close

4x3y=4. 3x=2y4

2r+3s=29,3r+2s=16