Posted by Devon on Friday, July 9, 2010 at 12:39am.
I see a "common" factor of (x-2) , so ...
(3x + 5) (x - 2) + (2x - 3) (x - 2)
= (x-2)[(3x+5) + (2x-3)]
= (x-2)(5x+2)
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