February 24, 2017

Homework Help: Calculus/Physics

Posted by Elisabeth on Thursday, July 8, 2010 at 10:32pm.

A stone is thrown from a cliff top with an upward velocity of 20 m/s. It takes 7 seconds for the stone to hit the ground at the bottom of the cliff. How high is the cliff?

I know you use the equation of motion
S(t)= (So)+(Vo)t-(1/2)gt^2
S(20)= (So) + 140 - 240.1
(So) = -100.1 m (I know it is supposed to be a positive number)
But doesn't that give you the total height? How do I get rid of the height of the parabola above the cliff?

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