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March 5, 2015

March 5, 2015

Posted by **Riss** on Thursday, July 8, 2010 at 9:37pm.

- Physics -
**tchrwill**, Saturday, July 10, 2010 at 10:34amVertical height h = V^2(sin^µ)/2g.

Horizontal distance = d = V^2(sin2µ)/g.

h = height, meters V = initial launch velocity, m/s, g = acceleration due to gravity, m/s^2s and µ = the elevation angle of the rocket measured from the horizontal to the launch directiion.

Thus, h = V^2(sin^2µ)/2g = 100 and

......d = V^2(sin2µ)/g = 300.

Solve for V^2, equate the results and solve for µ and then V.

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