Thursday

July 24, 2014

July 24, 2014

Posted by **Riss** on Thursday, July 8, 2010 at 9:37pm.

- Physics -
**tchrwill**, Saturday, July 10, 2010 at 10:34amVertical height h = V^2(sin^µ)/2g.

Horizontal distance = d = V^2(sin2µ)/g.

h = height, meters V = initial launch velocity, m/s, g = acceleration due to gravity, m/s^2s and µ = the elevation angle of the rocket measured from the horizontal to the launch directiion.

Thus, h = V^2(sin^2µ)/2g = 100 and

......d = V^2(sin2µ)/g = 300.

Solve for V^2, equate the results and solve for µ and then V.

**Related Questions**

physics - Short projectile motion question A German rocket from the second ...

math - Short projectile motion question A German rocket from the second world ...

Math - Using h(t)=gt^2+v0t+h0, where g= -16, h0= initial height, v0= initial ...

Algebra: Quadratic Functions - A model rocket is launched with an initial ...

physics - A rocket moves straight upward, starting from rest with an ...

physics - A rocket moves straight upward, starting from rest with an ...

calculus - The height (in feet) attained by a rocket t seconds into flight is ...

calc 2 - The height (in feet) attained by a rocket t seconds into flight is ...

Physics - A model rocket launches with an initial velocity of 6 m/s, at an angle...

physics - A model rocket is launched straight upward with an initial speed of 47...