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March 29, 2015

March 29, 2015

Posted by **Akashdeep** on Thursday, July 8, 2010 at 7:23am.

v = (2t^2+5)cm/s. Find:-

(i) The change in velocity of the particle during the time interval t1 = 2s and t2 = 4s.

(ii) Average acceleration during the same interval.

(iii) Instantenous acceleartion at t = 4s.

Please SOLVE it!!!

- Grade 11th Physics -
**drwls**, Thursday, July 8, 2010 at 8:26am(i) Use the formula you havebeen given to compute v at t = 4 and t = 2 s. Compute the change in v:

v(4) - v(2) = 37 - 13 = ____ cm/s

(ii) Divide the result of (i) by 2 s.

(iii) Compute the formula for derivative of v(t).

It is a(t) = dv/dt = 4t.

That is the instantaneous acceleration. Evaluate it at t = 4s.

Fill in the blanks. You could use the exercise.

- Grade 11th Physics -
**Akashdeep**, Thursday, July 8, 2010 at 8:36amSir I want the answers so i could match my answers with yours

- Grade 11th Physics -
**drwls**, Thursday, July 8, 2010 at 9:06amThen show your answers

- Grade 11th Physics -
**Akashdeep**, Thursday, July 8, 2010 at 2:47pmSir i'll solve tommorrow and show you. I hope you get back to this question tommorow

- Grade 11th Physics -
**drwls**, Thursday, July 8, 2010 at 6:59pmI have already shown you how to do the three problems. Each requires one step. I will be happy to verify that you have followed directions

- Grade 11th Physics -
**Akash**, Friday, July 9, 2010 at 5:19amSir my teacher solved it!!!

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