Grade 11th Physics
posted by Akashdeep on .
This question is based upon differential calculus. Velocity of the particle is given by the equation:
v = (2t^2+5)cm/s. Find:-
(i) The change in velocity of the particle during the time interval t1 = 2s and t2 = 4s.
(ii) Average acceleration during the same interval.
(iii) Instantenous acceleartion at t = 4s.
Please SOLVE it!!!
(i) Use the formula you havebeen given to compute v at t = 4 and t = 2 s. Compute the change in v:
v(4) - v(2) = 37 - 13 = ____ cm/s
(ii) Divide the result of (i) by 2 s.
(iii) Compute the formula for derivative of v(t).
It is a(t) = dv/dt = 4t.
That is the instantaneous acceleration. Evaluate it at t = 4s.
Fill in the blanks. You could use the exercise.
Sir I want the answers so i could match my answers with yours
Then show your answers
Sir i'll solve tommorrow and show you. I hope you get back to this question tommorow
I have already shown you how to do the three problems. Each requires one step. I will be happy to verify that you have followed directions
Sir my teacher solved it!!!