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Grade 11th Physics

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This question is based upon differential calculus. Velocity of the particle is given by the equation:
v = (2t^2+5)cm/s. Find:-

(i) The change in velocity of the particle during the time interval t1 = 2s and t2 = 4s.
(ii) Average acceleration during the same interval.
(iii) Instantenous acceleartion at t = 4s.

Please SOLVE it!!!

  • Grade 11th Physics -

    (i) Use the formula you havebeen given to compute v at t = 4 and t = 2 s. Compute the change in v:
    v(4) - v(2) = 37 - 13 = ____ cm/s

    (ii) Divide the result of (i) by 2 s.

    (iii) Compute the formula for derivative of v(t).
    It is a(t) = dv/dt = 4t.
    That is the instantaneous acceleration. Evaluate it at t = 4s.

    Fill in the blanks. You could use the exercise.

  • Grade 11th Physics -

    Sir I want the answers so i could match my answers with yours

  • Grade 11th Physics -

    Then show your answers

  • Grade 11th Physics -

    Sir i'll solve tommorrow and show you. I hope you get back to this question tommorow

  • Grade 11th Physics -

    I have already shown you how to do the three problems. Each requires one step. I will be happy to verify that you have followed directions

  • Grade 11th Physics -

    Sir my teacher solved it!!!

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