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chemistry

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I need help solving this question.. An aqueous solution of ethylene glycol (C2H6O2) IS 40% ethylene glycol by mass, and has a density of 1.05g/ml. what are the molarity, molality fraction of the solution?

  • chemistry - ,

    A gas occupies 10 liters at standard conditions. what volume will it occupy at 20 C and 700 torr?

  • chemistry - ,

    I don't know what you mean by molality fraction.
    mass of 1,000 mL = 1.05 g/mL x 1000 = 1050 gram. That is 40% ethylene glycol; therefore,
    1050 x 0.40 = 420 g ethylene glycol and 420 g is 420/molar mass ethylene glycol. That will give you moles/L which is M.

    To find molality,
    1050 grams soln - mass ethylene glycol (420 g) = 630 g water.
    molality = moles/kg soln. Convert 420 to moles ethylene glycol and divide by 0.630 = ?? molal

  • chemistry - ,

    For the gas problem use PV = nRT.

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