Posted by **Shoaib** on Wednesday, July 7, 2010 at 8:32am.

A car tyre has a volume of 10 L when inflated. The tyre is inflated to a pressure of 3 atm at 17°C with air. Due to driving, the temperature of the tyre increases to 47°C.

a) what would be the pressure at this temperature?

b) how many litres of air measured at 47°C and pressure of 1 atm should be let out to restore the tyre to 3 atm at 47°C?

- Chemistry -
**DrBob222**, Wednesday, July 7, 2010 at 9:47am
a.

(P1/T1) = (P2/T2)

b.

(P1V1/T1)= (P2V2/T2)

- Chemistry -
**Shoaib**, Wednesday, July 7, 2010 at 11:20am
I still am confused about the part B of the question. plz explain

- Chemistry -
**DrBob222**, Wednesday, July 7, 2010 at 12:24pm
I am too, but try this.

PV = nRT and plug in 3.31 atm, 10L, 320 K, and calculate n. That will be the number of moles at 290K as well as at 320 K. Then redo PV = nRT using 320K, 3 atm, then subtract moles at 3.31 atm from moles at 3 atm. That will be the moles that must be released. Then PV = nRT and plug in the new conditions for air to ber released. If I didn't goof the volume to be released is about 3 L *(@ 47 C and 1 atm P).

- Chemistry -
**Shoaib**, Thursday, July 8, 2010 at 12:35am
Yea it works. we get 3.1 litre. thanks a lot..

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