How many grams of ammonia are formed when 1.34 grams of nitrogen react with an excess of hydrogen(3 H2 + N2 reacts to form 2 NH3)(Answer to tenths ex. 2.5)?
Write the equation and balance it.
N2 + 3H2 ==> 2NH3
Convert 1.34 g N2 to moles. moles = grams/molar mass.
Using the coefficients in the balanced equation, convert moles N2 to moles NH3.
Convert moles NH3 to grams. g = moles x molar mass. Round to the tenths place.
Post your work if you get stuck.
Well, let me put on my chemistry clown hat and juggle some numbers for you!
According to the balanced equation, 3 moles of hydrogen react with 1 mole of nitrogen to form 2 moles of ammonia. Now, we need to find out the number of moles of nitrogen in 1.34 grams.
The molar mass of nitrogen (N2) is approximately 28 grams/mol. So, we can calculate the number of moles of nitrogen using the formula:
moles = mass / molar mass
moles = 1.34 grams / 28 grams/mol ≈ 0.048 moles of nitrogen
Now, since the reaction ratio is 3:1 between nitrogen and ammonia, we can say that 0.048 moles of nitrogen will produce (0.048 moles * 2 moles ammonia/1 mole nitrogen) = 0.096 moles of ammonia.
Finally, let's convert moles to grams of ammonia. The molar mass of ammonia (NH3) is approximately 17 grams/mol.
grams = moles * molar mass
grams = 0.096 moles * 17 grams/mol ≈ 1.6 grams of ammonia
Voila! Approximately 1.6 grams of ammonia are formed when 1.34 grams of nitrogen react with an excess of hydrogen. Keep in mind that this is just a rough answer to tenths, so don't put it in a clown car and try to balance it!
To determine the number of grams of ammonia formed, we need to use the stoichiometry of the balanced equation.
The balanced equation for the reaction is: 3 H2 + N2 -> 2 NH3
From the equation, we can see that 3 moles of hydrogen react with 1 mole of nitrogen to produce 2 moles of ammonia.
To find the number of moles of nitrogen in 1.34 grams, we need to use the molar mass of nitrogen (N2), which is approximately 28 grams/mol.
Number of moles of nitrogen = mass / molar mass
Number of moles of nitrogen = 1.34 grams / 28 grams/mol
Number of moles of nitrogen = 0.048 moles
According to the stoichiometry of the balanced equation, 1 mole of nitrogen reacts to produce 2 moles of ammonia.
Number of moles of ammonia = 0.048 moles x (2 moles NH3/1 mole N2)
Number of moles of ammonia = 0.096 moles
To find the mass of ammonia formed, we need to use the molar mass of ammonia (NH3), which is approximately 17 grams/mol.
Mass of ammonia = number of moles x molar mass
Mass of ammonia = 0.096 moles x 17 grams/mol
Mass of ammonia = 1.63 grams (rounded to the nearest tenth)
Therefore, approximately 1.6 grams of ammonia are formed when 1.34 grams of nitrogen react with an excess of hydrogen.
To find out how many grams of ammonia are formed when nitrogen reacts with hydrogen, we need to use stoichiometry. Stoichiometry is a mathematical relationship between the amounts of reactants and products in a balanced chemical equation.
1. Write the balanced chemical equation for the reaction:
3 H2 + N2 → 2 NH3
2. Calculate the molar mass of N2 and NH3:
- N2: Nitrogen (N) has a molar mass of 14.01 g/mol. Since there are two nitrogen atoms in N2, the molar mass of N2 is 2 * 14.01 g/mol = 28.02 g/mol.
- NH3: Nitrogen (N) has a molar mass of 14.01 g/mol, and Hydrogen (H) has a molar mass of 1.01 g/mol. Since there are three hydrogen atoms in NH3, the molar mass of NH3 is 14.01 g/mol + 3 * 1.01 g/mol = 17.03 g/mol.
3. Calculate the number of moles of nitrogen (N2):
To find the number of moles, divide the given mass by the molar mass:
Number of moles of N2 = Mass of N2 / Molar mass of N2 = 1.34 g / 28.02 g/mol ≈ 0.048 moles
4. Use the balanced chemical equation to determine the stoichiometric ratio of moles between nitrogen and ammonia:
From the balanced equation, we can see that the ratio is 1:2 between nitrogen and ammonia.
5. Calculate the number of moles of NH3 formed:
Since the stoichiometric ratio is 1:2, the number of moles of NH3 formed will be twice the number of moles of N2:
Number of moles of NH3 = 0.048 moles * 2 = 0.096 moles
6. Calculate the mass of ammonia formed:
To find the mass, multiply the number of moles by the molar mass of NH3:
Mass of NH3 = Number of moles of NH3 * Molar mass of NH3 = 0.096 moles * 17.03 g/mol ≈ 1.64 grams
So, approximately 1.64 grams of ammonia are formed when 1.34 grams of nitrogen react with an excess of hydrogen.