Posted by Pat on Tuesday, July 6, 2010 at 2:27pm.
Assume 10 ft is the top of the trajectory. (Acually, a good free throw shooter would aim higher than that.) The ball must rise 3 feet in the time it takes to travel horizontally 13 feet. Let T be the travel time from release until it is at the basket. Let V be the release velocity.
Vcos55*T = 13 ft
Vsin55 = g T where g is the acceleration of gravity, 32.2 ft^2/s.
tan 55 = gT^2/13
T^2 = (13/32.2)tan55 = 0.577 sec^2
T = 0.759 sec
Now solve for V
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