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February 26, 2015

February 26, 2015

Posted by **Jane** on Monday, July 5, 2010 at 2:40pm.

(a) In straight-line distance, how far is city C from city A?

(b) Relative to city A, in what direction is city C?

- College Physics -
**Damon**, Monday, July 5, 2010 at 2:51pmLaw of cosines

b^2 = a^2+c^2-2ac cos B

b^2 = 240^2 + 200^2 -2(240)(200)cos(180-31)

solve for b which is distance from A to C

then law of sines

sin A/240 = sin(180-31)/b

solve for angle A

- College Physics -
**Anonymous**, Saturday, October 23, 2010 at 4:39pmAs a sailboat sails 59.0 m due north, a breeze exerts a constant force 1 on the boat's sails. This force is directed at an angle west of due north. A force 2 of the same magnitude directed due north would do the same amount of work on the sailboat over a distance of just 36.0 m. What is the angle between the direction of the force 1 and due north?

- College Physics -
**Cory**, Wednesday, October 19, 2011 at 11:45pmbecause it says the two forces do the same amount of work, you can tell that the two distances given are the hypotenuse and leg of a right triangle. after that it's just a matter of taking the inverse cos of adjacent/hypotenuse

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