Posted by **Julie Anne** on Monday, July 5, 2010 at 9:26am.

lisa left home in a car that was traveling at the rate of 48 km/hr. she walked home at the rate of 6 km/hr. the round trip took 1.5 how far did lisa ride?

- MAth word problem -
**Reiny**, Monday, July 5, 2010 at 9:34am
One of the best ways to do these is by using a "chart"

on the top: distance --- rate --- time

one the side: the two cases, in this problem: by car , walking

....... dist........rate....time

car ...48t ...... 48 ...... t

walk 6(1.5-t) .. 6 ..... (1.5-t)

So where does the equality come in ????

Ahhh, their distances are the same!

so solve

48t = 6(1.5-t)

( I get t = 1/6 and

distance = 48(1/6) = 8 )

- MAth word problem -
**Julie Anne**, Monday, July 5, 2010 at 9:40am
thank you reiny^_^

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