Posted by Julie Anne on Monday, July 5, 2010 at 9:26am.
One of the best ways to do these is by using a "chart"
on the top: distance --- rate --- time
one the side: the two cases, in this problem: by car , walking
....... dist........rate....time
car ...48t ...... 48 ...... t
walk 6(1.5-t) .. 6 ..... (1.5-t)
So where does the equality come in ????
Ahhh, their distances are the same!
so solve
48t = 6(1.5-t)
( I get t = 1/6 and
distance = 48(1/6) = 8 )
thank you reiny^_^
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