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July 22, 2014

July 22, 2014

Posted by **theo** on Sunday, July 4, 2010 at 6:14pm.

(x+y)/(x-y)= x^2 + y^2; dx/dt = 12, x = 1, y = 0

- calculus -
**bobpursley**, Sunday, July 4, 2010 at 6:20pmmultipy both sides by (x-y)

x+y=x^3 -yx^2-xy^2-y^3 check that.

dx/dt+dy/dt= 3x^2 dx/dt-2yx dx/dt-x^2dy/dt-y^2dx/dt-3y^2 dy/dt

gather terms....

dx/dt(1-3x^2+2yx+3y^2)=dy/dt (-1-x^2-3y^2)

check that carefully, it is easy to make an error in sign.

solve for dy/dt

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