Saturday

October 10, 2015
Posted by **Kate** on Sunday, July 4, 2010 at 2:44pm.

Finding the percent heterozygous should be as sipmle as 2(.5)(.5)=.5 I got .5 for g by simply taking the complement of the dominant trait G, gray, by doing 1-.5

Clearly I am doing something wrong. I do not know what I am doing wrong. Iw as woudnering if you could tell me the secret to this question as I can not get .67 for the life of me

Only 28% of the people who took this test got this question right and I can't figuer it out either...

h t t p : / / i m g 5 2 6 . i m a g e s h a c k . u s / i m g 5 2 6 / 4 6 7 7 / b i o f . p n g

Assuming that the population was in

Hardy-Weinberg equilibrium for the G locus, what percentage of the gray moths that emerged in 1980 was heterozygous?

(A) 0%

(B) 25%

(C) 33%

(D) 67%

(E) 100%

- Biology/math expert needed -
**SraJMcGin**, Sunday, July 4, 2010 at 7:33pmFirst of all this looks like math, which I do NOT touch! However the following may help someone who can help you:

1. the link = (Broken Link Removed)

2. Hardy-Weinberg equilibrium =

http://search.yahoo.com/search?fr=mcafee&p=Hardy-Weinberg+equilibrium

3. Allele = http://search.yahoo.com/search?fr=mcafee&p=G+Allele

4. heterozygous = http://search.yahoo.com/search?fr=mcafee&p=heterozygous

Good luck!

Sra (aka Mme)

- Biology -
**Damon**, Monday, July 5, 2010 at 4:27amSorry, my original field was physics and my graduate degrees are in in engineering. Any high school student has more background in biology than I have.

- Biology -
**Brandon**, Monday, April 25, 2011 at 11:31pmWhat you did was all right, but they're not asking a normal question involving all of the moths. They're asking for the percentage out of only the grey moths, which eliminates the moths with the gg phenotype.

Another, more useful way of finding the percent of heterozygous moths is using the formula

2pq = 1 - p^2 - q^2

*p is the frequency of the dominant gene, so p^2 is the % of the homozygous dominant moths (GG)

*q is the frequency of the recessive gene, so q^2 is the % of the homozygous recessive moths (gg)

As you said, p and q were both 0.5, so when they are squared, they both turn out to be 0.25. When we put them into the formula, we get

2pq = 1 - 0.25 - 0.25

= o.5

which is what you got as your answer.

However, since the question asks us for the percentage out of only the grey moths, we do not include the gg phenotypes as part of the final calculation. What's left is 75% of the population, of which 2/3 are heterozygous. That, converted into decimal form is 0.67, or 67%.