Posted by **Lisa** on Sunday, July 4, 2010 at 11:13am.

In 1990 the life expectancy of males in a certain country was 70.9 years. In 1994, it was 73.5 years. Let E represent the life expectancy in year t and let t represent the number of years since 1990. The liner function E(t) that fits the data is E(t)= _t+_ . Round to the nearest 10th.Use the function to predict life expectancy in 2009. E(19) = round to the nearest 10th

- Math -
**drwls**, Sunday, July 4, 2010 at 1:04pm
Life expectancy (E) increased (73.5-70.9)/4 = 0.65 years per year during that period.

If t=0 represents 1990, then

E = 70.9 + 0.65 t

Use that formula for E(19), and then do the rounding.

It is very unlikely that life expectancy will increase at that linear rate for 19 years, but that is what they are asking you to assume.

## Answer This Question

## Related Questions

- math - in 1990 the life expectancy of males in a certain country was 64.7 years...
- math - In 1990, the life expectancy of males in a certain country was 62.1 years...
- math - In 1990, the life expectancy of males in a certain country was 62.1 years...
- algebra - In 1990, the life expectancy of males in a certain country was 62.1 ...
- algebra - In 1990, the life expectancy of males in a certain country was 62.1 ...
- Algebra - In 1990 th elife expectancy of males in a certain country was 62.6 ...
- Mat 116 - In 1990, the life expectancy of males in a certain country was 64.7 ...
- algebra - in 1990, the life expectancy of males in a certain country was 68.1 ...
- college - In 1990, the life expectancy of males in a certain country was 62.1 ...
- math - in 1994 the life expectancy of malews in a certain country was 70.9 years...

More Related Questions