a 10.0-ml sample of aqueous HCL requires 24.32ml of 0.134M NaOH to reach the endpoint, what is the molar concentration of H2SO4
Oh, H2SO4 wants to play too? Well, let's calculate its concentration then!
To do that, first, we need to find the number of moles of NaOH used in the reaction. We can do this by multiplying the volume of NaOH used (in liters) by its molar concentration.
Are you ready for some calculations? Shall we dive into this chemical comedy routine? *wink, wink*
To determine the molar concentration of HCl, we can use the equation:
M1V1 = M2V2
Where:
M1 = Molar concentration of NaOH (0.134 M)
V1 = Volume of NaOH required to reach the endpoint (24.32 mL)
M2 = Molar concentration of HCl
V2 = Volume of HCl used (10.0 mL)
Plugging in the values we know:
(0.134 M)(24.32 mL) = M2(10.0 mL)
Solving for M2:
M2 = (0.134 M)(24.32 mL) / (10.0 mL)
M2 = 0.3257 M
Therefore, the molar concentration of HCl is approximately 0.3257 M.
To find the molar concentration of H2SO4, we can use the concept of stoichiometry and the volume and concentration of NaOH required to neutralize the HCl.
First, let's write the balanced chemical equation for the reaction between HCl and NaOH:
HCl + NaOH -> NaCl + H2O
From the equation, we can see that the stoichiometric ratio between HCl and NaOH is 1:1. This means that one mole of HCl reacts with one mole of NaOH.
Given that it takes 24.32 ml of 0.134 M NaOH to reach the endpoint, we can calculate the moles of NaOH used:
moles of NaOH = volume of NaOH (in liters) x concentration of NaOH
volume of NaOH = 24.32 ml = 24.32 ml x (1 L / 1000 ml) = 0.02432 L
moles of NaOH = 0.02432 L x 0.134 M = 0.00326 moles
Since the stoichiometric ratio of HCl and NaOH is 1:1, the moles of HCl used will also be 0.00326 moles.
The volume of the HCl solution is 10.0 ml, which can be converted to liters:
volume of HCl (in liters) = 10.0 ml x (1 L / 1000 ml) = 0.01 L
Finally, we can calculate the molar concentration of HCl (H2SO4) using the equation:
molar concentration of HCl (H2SO4) = moles of HCl / volume of HCl (in liters)
molar concentration of HCl (H2SO4) = 0.00326 moles / 0.01 L = 0.326 M
Therefore, the molar concentration of H2SO4 is 0.326 M.
Equation.
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
moles NaOH used = M x L = ??
moles H2SO4 = 1/2 mole NaOH.
M H2SO4 = moles/L. You know moles and L, solve for M.