Tuesday

July 22, 2014

July 22, 2014

Posted by **Madasan** on Saturday, July 3, 2010 at 11:58am.

x = 1/2 a t^2

Now, I know I would graph x versus t, but do I graph:

-x versus t

-x versus the root of t

-x versus t^2

-or possibly x^2 versus t???

Soo confusing!

Please help!

Thank you so so so much!

- Calculus please help! -
**Madasan**, Saturday, July 3, 2010 at 11:59amand please explain why so I understand how to do this!

thanks again!

- Calculus please help! -
**bobpursley**, Saturday, July 3, 2010 at 1:13pmwell, it makes no sense.

I assume you have a set of data points. If so, plot them. Is it a straight line, or a second degree curve? If it is a straight line, then use y=mt+b and find m, b from your data plot. If it is a parabola, use y=at^2+ b, and find a,b to match the points.

- Calculus please help! -
**Damon**, Saturday, July 3, 2010 at 4:55pmGraph x versus t^2

- Calculus please help! -
**Damon**, Saturday, July 3, 2010 at 4:58pmHere is the answer I gave to the same question yesterday:

============================

I would graph x versus t^2 but is that correct?

Thank you very much!

* Math/Calculus - Damon, Friday, July 2, 2010 at 8:36pm

Sure, that will work.

You could also use a sheet of graph paper with log scales.

log x = log [.5 a t^2] = log(.5 a) + 2 log t

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