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December 20, 2014

December 20, 2014

Posted by **Warren** on Friday, July 2, 2010 at 8:22pm.

x = 1/2at^2

I would graph x versus t^2 but is that correct?

Thank you very much!

- Math/Calculus -
**Damon**, Friday, July 2, 2010 at 8:36pmSure, that will work.

You could also use a sheet of graph paper with log scales.

log x = log [.5 a t^2] = log(.5 a) + 2 log t

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