what volumes of the folowing concentrated solutions are required to prepare solutions of the final concentrations indicated (a) 12MH2SO4 to prepare 2.0 L 0f 1.5 MH2SO4 (B)2.0 MKCIto prepare 200ML 0f 0.5MKCI
mL A x M A = mL B x M B.
Calculate the ph of 1.5mh2so4.
16l
To find the volume of concentrated solution needed to prepare a solution of a desired concentration, you can use the formula:
(V1)(C1) = (V2)(C2)
Where:
V1 = Volume of concentrated solution
C1 = Concentration of concentrated solution
V2 = Volume of final solution
C2 = Concentration of final solution
(a) 12M H2SO4 to prepare 2.0 L of 1.5 M H2SO4:
Using the formula, we can plug in the given values:
(V1)(12M) = (2.0L)(1.5M)
Rearranging the formula to solve for V1, we get:
V1 = (2.0L)(1.5M) / 12M
V1 = (2.0L)(0.125)
V1 = 0.25 L or 250 mL
Therefore, you would need 250 mL of the 12M H2SO4 solution to prepare 2.0 L of 1.5 M H2SO4.
(b) 2.0 M KCI to prepare 200 mL of 0.5 M KCI:
Using the formula, we can plug in the given values:
(V1)(2.0M) = (200mL)(0.5M)
Rearranging the formula to solve for V1, we get:
V1 = (200mL)(0.5M) / 2.0M
V1 = (200mL)(0.25)
V1 = 50 mL
Therefore, you would need 50 mL of the 2.0 M KCI solution to prepare 200 mL of 0.5 M KCI.