The 10th grade raffle sold 127 tickets. If they award 1st and 2nd prize, how many different pairs of winners are possible?
a) 16,129
b) 254
c) 16,002
d) 8,001
the answer i picked was c
correct. 127*126
thanks bobpursley
To calculate the number of different pairs of winners in the 10th grade raffle, we need to use the concept of combinations.
First, we need to determine how many ways we can choose the 1st prize winner. Since there are 127 tickets sold, there are 127 possible choices for the 1st prize winner.
Next, we need to determine how many ways we can choose the 2nd prize winner. After choosing the 1st prize winner, there are 126 remaining tickets. Therefore, there are 126 possible choices for the 2nd prize winner.
To find the total number of different pairs of winners, we need to multiply the number of choices for the 1st prize and the number of choices for the 2nd prize. Thus, the total number of different pairs of winners is:
127 * 126 = 16,002
So, the correct answer is c) 16,002.