Posted by rani on .
if cot theta =7/8 , evaluate (1+sin^2theta)(1sin^2theta)/(1+cost^2theta)(1+co^2theta)
the answer should be 49/64 but i couldn't get that answer. can any one help?

maths 
rani,
if cot theta =7/8 , evaluate (1+sin^2theta)(1sin^2theta)/(1+cos^2theta)(1+cos^2theta)
the answer should be 49/64 but i couldn't get that answer. can any one help? 
maths 
Reiny,
if cotØ = 7/8, then tanØ = 8/7
make a sketch of the corresponding rightangled triangle to find the hypotenuse to be √113
so sinØ = 8/√113 and cosØ = 7/√113
then (1+sin^2theta)(1sin^2theta)/(1+cos^2theta)(1+cos^2theta)
= (1+64/113)(164/113)/(1+49/113)^2
= (1  64^2/113^2)/(162/113)^2
= (8673/113^2) / (26244/13^2)
= 8673/2644
≠ 49/64
check your typing of the expression, the end part of
cos^2theta makes no sense