Posted by Todd on Wednesday, June 30, 2010 at 10:46pm.
Velocity (v) obeys the equation
v = Vo - gt = Vo - 9.8 t
where Vo is the initial velocity
At t=2 s
32 = Vo - 19.6 m
Therefore Vo = 51.6 m/s
y (the height) = Vo t - (g/2)t^2
= 51.6 t - 4.9 t^2
Set y = 16 and solve for the time t when that height is reached. Take the lowest of the two solutions of the quadratic equation; the other is the time coming back down.
Related Questions
Physics - You shoot an arrow into the air. Two seconds later (2.00 {\rm s}) the ...
Phy - You shoot an arrow into the air. Two seconds later (2.00 {\rm s}) the ...
Physics - You shoot an arrow into the air. 2.oo seconds later the arrow has gone...
physics - An arrow is shot verticaaly upward. Two seconds later, it is at a ...
Physics - An arrow is shot straight upward at 55 m/s. a) find the time until the...
Physics - An arrow is shot straight upward at 55 m/s. a) find the time until the...
Physics - An arrow is shot straight upward at 55 m/s. a) find the time until the...
physics - You shoot an arrow straight up into the air using a bow. You have ...
algebra - an arrow is shot into the air with an initial velocity of 96 feet per ...
Physics 11 - Mark Ji shoots a 40gram arrow straight up in the air at 30m/s ...
For Further Reading
