Posted by **Ana** on Wednesday, June 30, 2010 at 9:55pm.

I have a 45-45 special right triangle who's hypotenuse is 12, how do I find the other two side lengths?

- Geometry -
**Henry**, Wednesday, June 30, 2010 at 10:27pm
Since the 2 angles are equal, the 2 sides are also equal.We'll call the

horizontal side X and the vertical side Y. X=12*Cos45=8.48, Y=12*Sin45=8.48. NOTE: the sin45=Cos45.

- Geometry -
**PsyDAG**, Thursday, July 1, 2010 at 3:04pm
Since they are of equal length, let a = length of each side.

Pythagorean theorem = a^2 + a^2 = hypotenuse^2

Therefore 2a^2 = 12^2

Can you take it from there?

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