Posted by **Meredith** on Wednesday, June 30, 2010 at 5:59pm.

Pump A, working alone, can fill a tank in 3 hours, and pump B can fill the same tank in 2 hrs. If the tank is empty to start and pump A is switched on for one hour, after which pump B is also switched on and the two work together, how many minutes will pump B have been working by the time the pool is filled?

a)48

b)50

c)54

d)60

e)64

- Algebra I -
**Damon**, Wednesday, June 30, 2010 at 6:10pm
pump A, 1/3 tank /hr

pump B, 1/2 tank/hr

in first hour pump A fills 1/3 tank

so together they fill 2/3 tank

x hours (1/3 tank/hr + 1/2 tank/hr) = 2/3 tank

x (5/6) = 2/3 = 4/6

5 x = 4

x = 4/5 hr = (4/5)60 = 48 minutes

## Answer this Question

## Related Questions

- maths - One pump fills a tank two times as fast as another pump. If the pumps ...
- Algebra - a worker has a new pump and an old pump. the new pump can fill a tank...
- Algebra - 2 pumps can fill a water tank in 45 minutes when working together. ...
- algebra - Two pumps can fill a water tank in 256 minutes when working together. ...
- algebra - Pump A can fill a swimming pool in 6 hours and pump B can fill the ...
- math - Filling a tank. Two pipes are connected to the same tank. Working ...
- math - If pump A and pump B work together, they can fill a pool in 4 hours. Pump...
- physics - a pump fills a tank of capacity 300 m^3 in 5 hours.the tank is ...
- college algebra - A paint-mixing machine has 2 inlet pipes. One takes 1 hour ...
- Math - Each of three pumps A, B, C can pump water either into, or out of, a ...

More Related Questions