Posted by **Meredith** on Wednesday, June 30, 2010 at 5:59pm.

Pump A, working alone, can fill a tank in 3 hours, and pump B can fill the same tank in 2 hrs. If the tank is empty to start and pump A is switched on for one hour, after which pump B is also switched on and the two work together, how many minutes will pump B have been working by the time the pool is filled?

a)48

b)50

c)54

d)60

e)64

- Algebra I -
**Damon**, Wednesday, June 30, 2010 at 6:10pm
pump A, 1/3 tank /hr

pump B, 1/2 tank/hr

in first hour pump A fills 1/3 tank

so together they fill 2/3 tank

x hours (1/3 tank/hr + 1/2 tank/hr) = 2/3 tank

x (5/6) = 2/3 = 4/6

5 x = 4

x = 4/5 hr = (4/5)60 = 48 minutes

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