Saturday

August 2, 2014

August 2, 2014

Posted by **Sam** on Wednesday, June 30, 2010 at 3:31pm.

Any help on this would be very much appreciated.

The graph y=3x^2+6x+9 is a parabola, I need to use algebra to find the equation of the axis of symmetry, I then need to use this information to find the coordinates of the vertex.

Any ideas? Many thanks

- Algebra -
**Damon**, Wednesday, June 30, 2010 at 4:56pm3x^2+6x+9 = y

x^2 + 2x + 3 = y/3

x^2 + 2 x = y/3 - 3

x^2 + 2x + 1 = y/3 - 2

(x+1)^2 = (1/3)(y-6)

symmetric about the vertical line x = -1 where (x+1) = 0

vertex at that point where x = -1 then y-6 = 0 and y = 6 so vertex at (-1,6)

**Related Questions**

math help,algebra - Okay this is what i have to do but i think i am doing ...

Exploring Quadratic Graphs - ok, I totally did not get this question at all. ...

Quadratic Equations and Functions - I started having trouble on part (c), and I ...

Quadratic Equations and Functions - I started having trouble on part (c), and I ...

ALGEBRA 1 - Please check for me.Without drawing the graph of the given equation ...

ALGEBRA 1 - Please check for me.Without drawing the graph of the given equation ...

Parabola Help - by plotting the graph of parabola y=2+3x-2x^2 which 3 option are...

Algebra - Hi, I need to use algebra to find the x-and y-intercepts for the ...

Algebra 2 - I have a question and I can not figure it out. Any answers to the ...

Algebra II - In this set of eight problems, we have to match each equation with ...